# Integer division in C

Integer division in modern C always rounds towards zero.
For example:

```9/2 = 4
-9/2 = -4 (not -5)
```

This was was not always so. In early C versions and in the C89 standard, positive integer division rounded to zero, but result of negative integer division was implementation dependent!

From §3.3.5 Multiplicative operators of the C89 standard:

```   When integers are divided and the division is inexact, if both
operands are positive the result of the / operator is the largest
integer less than the algebraic quotient and the result of the %
operator is positive.  If either operand is negative, whether the
result of the / operator is the largest integer less than the
algebraic quotient or the smallest integer greater than the algebraic
quotient is implementation-defined, as is the sign of the result of
the % operator.  If the quotient a/b is representable, the expression
(a/b)*b + a%b shall equal a .
```

The same appears in the first edition of The C Programming Language book by Kernighan and Ritchie.

This implementation-defined behavior was fixed by the C99 standard which defined that integer division always rounds towards zero.

From §6.5.5 Multiplicative operators of the C99 standard:

```When integers are divided, the result of the / operator is the algebraic
quotient with any fractional part discarded.
```

Thanks to Arch for pointing this out.

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